Solutions for the stress and pore pressure $p$ are derived due to sudden introduction of a plane strain shear dislocation on a leaky plane in a linear poroelastic, fluid-infiltrated solid. For a leaky plane, $y=0$, the fluid mass flux is proportional to the difference in pore pressure across the plane requiring that $\Delta p=R\u2202p/\u2202y$, where $R$ is a constant resistance. For $R=0$ and $R\u2192\u221e$, the expressions for the stress and pore pressure reduce to previous solutions for the limiting cases of a permeable or impermeable plane, respectively. Solutions for the pore pressure and shear stress on and near $y=0$ depend significantly on the ratio of $x$ and $R$. For the leaky plane, the shear stress at $y=0$ initially increases from the undrained value, as it does from the impermeable plane, but the peak becomes less prominent as the distance $x$ from the dislocation increases. The slope ($\u2202\sigma xy/\u2202t$) at $t=0$ for the leaky plane is always equal to that of the impermeable plane for any large but finite $x$. In contrast, the slope $\u2202\sigma xy/\u2202t$ for the permeable fault is negative at $t=0$. The pore pressure on $y=0$ initially increases as it does for the impermeable plane and then decays to zero, but as for the shear stress, the increase becomes less with increasing distance $x$ from the dislocation. The rate of increase at $t=0$ is equal to that for the impermeable fault.