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TECHNICAL PAPERS

Equilibrium and Belt-Pulley Vibration Coupling in Serpentine Belt Drives

[+] Author and Article Information
L. Kong, R. G. Parker

Department of Mechanical Engineering, The Ohio State University, 206 W 18th Avenue, Columbus, OH 43210

J. Appl. Mech 70(5), 739-750 (Oct 10, 2003) (12 pages) doi:10.1115/1.1598477 History: Received March 17, 2002; Revised September 27, 2002; Online October 10, 2003
Copyright © 2003 by ASME
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References

Figures

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A prototypical three-pulley serpentine belt drive system
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Detail of tensioner region and pulley 2, defining alignment angles
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Equilibrium deflections of spans 1 and 3 for varying belt bending stiffness: s=0,ks=4, γ=400, P1=P2=P3=1
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Equilibrium deflections of spans 1 and 3 for varying span tensions: ε=0.05, s=0,ks=4, γ=400
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Equilibrium deflections of spans 1 and 3 for varying speed: ε=0.05, ks=4, γ=400, P1=P2=P3=1
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Equilibrium deflections of spans 1 and 3 for varying tensioner spring stiffness: ε=0.05, s=0, γ=400, P1=P2=P3=1
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Equilibrium deflections of spans 1 and 3 for varying longitudinal belt stiffness: ε=0.05, s=0,ks=4,P1=P2=P3=1
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System coupling indicator Γ for varying belt bending stiffness: s=0,ks=4, γ=400, P1=P2=P3=1
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System coupling indicator Γ for varying span tensions: ε=0.015, s=0,ks=4, γ=400
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System coupling indicator Γ for varying speed: ε=0.015, ks=4, γ=400, P1=P2=P3=1.η=0.78 corresponds to tensioner orientation β1=135.79 deg, β2=178.74 deg in Table 1; while η=0 corresponds to tensioner orientation β1=68.53 deg, β2=111.47 deg.
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Tension variation with different tensioner orientation: ks=4, γ=400, P1=P2=P3=1. (a) β1=135.79 deg, β2=178.74 deg, η=0.78. (b) β1=68.53 deg, β2=111.47 deg, η=0.
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Equilibrium deflections of the first and third spans: ε=0.01, s=0.6,ks=4, γ=400, P1=P2=P3=1
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Equilibrium deflections of the first and third spans: ε=0.01, s=0.9,ks=4, γ=400, P1=P2=0.9395,P3=1.5395

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